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108 lines
3.1 KiB
108 lines
3.1 KiB
14 years ago
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"""Filename matching with shell patterns.
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fnmatch(FILENAME, PATTERN) matches according to the local convention.
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fnmatchcase(FILENAME, PATTERN) always takes case in account.
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The functions operate by translating the pattern into a regular
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expression. They cache the compiled regular expressions for speed.
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The function translate(PATTERN) returns a regular expression
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corresponding to PATTERN. (It does not compile it.)
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"""
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import re
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__all__ = ["fnmatch","fnmatchcase","translate"]
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_cache = {}
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def fnmatch(name, pat):
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"""Test whether FILENAME matches PATTERN.
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Patterns are Unix shell style:
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* matches everything
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? matches any single character
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[seq] matches any character in seq
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[!seq] matches any char not in seq
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An initial period in FILENAME is not special.
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Both FILENAME and PATTERN are first case-normalized
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if the operating system requires it.
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If you don't want this, use fnmatchcase(FILENAME, PATTERN).
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"""
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import os
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name = os.path.normcase(name)
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pat = os.path.normcase(pat)
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return fnmatchcase(name, pat)
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def filter(names, pat):
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"""Return the subset of the list NAMES that match PAT"""
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import os,posixpath
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result=[]
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pat=os.path.normcase(pat)
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if not _cache.has_key(pat):
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res = translate(pat)
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_cache[pat] = re.compile(res)
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match=_cache[pat].match
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if os.path is posixpath:
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# normcase on posix is NOP. Optimize it away from the loop.
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for name in names:
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if match(name):
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result.append(name)
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else:
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for name in names:
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if match(os.path.normcase(name)):
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result.append(name)
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return result
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def fnmatchcase(name, pat):
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"""Test whether FILENAME matches PATTERN, including case.
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This is a version of fnmatch() which doesn't case-normalize
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its arguments.
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"""
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if not _cache.has_key(pat):
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res = translate(pat)
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_cache[pat] = re.compile(res)
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return _cache[pat].match(name) is not None
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def translate(pat):
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"""Translate a shell PATTERN to a regular expression.
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There is no way to quote meta-characters.
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"""
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i, n = 0, len(pat)
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res = ''
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while i < n:
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c = pat[i]
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i = i+1
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if c == '*':
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res = res + '.*'
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elif c == '?':
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res = res + '.'
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elif c == '[':
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j = i
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if j < n and pat[j] == '!':
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j = j+1
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if j < n and pat[j] == ']':
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j = j+1
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while j < n and pat[j] != ']':
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j = j+1
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if j >= n:
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res = res + '\\['
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else:
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stuff = pat[i:j].replace('\\','\\\\')
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i = j+1
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if stuff[0] == '!':
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stuff = '^' + stuff[1:]
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elif stuff[0] == '^':
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stuff = '\\' + stuff
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res = '%s[%s]' % (res, stuff)
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else:
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res = res + re.escape(c)
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return res + "$"
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